In this tutorial you will learn about the C Program to Check Leap Year and its application with practical example.
In this tutorial, you will learn to create a c program to find given year is a leap year or not.
Prerequisites
Before starting with this tutorial we assume that you are best aware of the following C programming topics:
- C Operators
- Conditional statement.
- Basic input output .
Example:
So logic behind to check whether a year is leap or not is:
Logic of Leap Year:
If the given value is completely divisible by 4, 100 and 400 then it is a leap year.
If the given value is divisible by 4 but not by 100 then it is a leap year.
Logic for not a Leap Year:
If the given value is not divisible by 4 then it is not a leap year
If the given value is divisible by 4 and 100 but not divisible by 400 then it is not a leap year.
For example,
- 1221 is not a leap year.
- 2000 is a leap year.
- 1890 is not a leap year.
Program to Check given year is a Leap Year or not.
Here fist we take a year from user and with help of logical operator(&& and ,|| or) we will check multiple condition in a single if statement and get the required result.
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#include <stdio.h> int main() { int year; printf("enter any year \n:"); scanf("%d",&year); //taking value from user.. if (year % 4 == 0 && year % 100!= 0 || year%400 == 0) //logic { printf("%d is a leap year", year); } else { printf("%d is not a leap year", year); } return(0); } |
Output
In our program, we have first declared and initialized a set variables required in the program.
- year =taking year value from user.
First of all take a value from user to check whether a year is leap or not is,
then we check if the given value is completely divisible by 4, 100 and 400 then it is a leap year.
If the given value is divisible by 4 but not by 100 then it is a leap year.
