In this tutorial you will learn about the Java Program to display odd numbers from 1 to n or 1 to 100 and its application with practical example.
In this tutorial, we will learn to create a Java Program to display odd numbers from 1 to n or 1 to 100 using Java programming.
Prerequisites
Before starting with this tutorial we assume that you are best aware of the following Java programming topics:
- Java Operators.
- Basic Input and Output function in Java.
- Class and Object in Java.
- Basic Java programming.
- If-else statements in Java.
- For loop in Java.
What is Odd Number.
A number is called odd that number cannot be divided exactly into pairs or we can say odd numbers, when divided by 2, gives remainder 1. (5%2==1).
Java Program to display odd numbers from 1 to n or 1 to 100
In this program we would print all odd number between “1 to n or 1 to 100” .first of we would take a value from user and find the Odd number between given numbers .let have a look at the code.
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// java program to find odd number between 1 to N import java.util.Scanner; class Odd_numbers { public static void main(String args[]) { //Declaring variables and taking values from user. Scanner in = new Scanner(System.in); System.out.println("Enter value of n"); int number = in.nextInt(); // Printing odd number from 1 to n.... System.out.print("Odd Numbers from 1 to "+number+" are: "); for (int i = 1; i <= number; i++) { if (i % 2 != 0) { System.out.print(i + " "); } } } } |
Output
Odd number between 1-100.
Odd number between 1-N. Value of n is 50.
In the above program, we have first declared and initialized a set variables required in the program.
- number= it will hold entered number.
- i= i for iteration.
After that we take a number from user and find odd number between the given number.
Here we can use for loops to display odd numbers:
- Using for Loop
- Using if-else Statement.
In order to check odd number, we divided the number from 1 to N by 2 if it leaves a remainder of 1,then the number is odd
and the print the values.. As shown in image above.
